Posted by bobby on Monday, April 18, 2011 at 9:35am.
if a circuit has a3.9k resistor and a5uf capacitor, find the current flow in the circuit at 0.005 seconds, if the maximum current flow in the circuit is 105mA

problem solving  Henry, Tuesday, April 19, 2011 at 4:43pm
T = RC = 3.9K * 5uF = 19.5 Milliseconds
= Time Constant.
t/T = 5ms / 19.5ms = 0.256.
i = 105*e^(t/T),
i = 105*e^(0.256) = 81.3mA.
NOTE: If R was in ohms and C in Farads,
the Time Constant would be in seconds.
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