Posted by **Fakaapo** on Monday, April 18, 2011 at 5:20am.

In how many ways can a committee of five people be selected from seven women and nine men if at least one woman must be in the committee?

- math -
**MathMate**, Monday, April 18, 2011 at 7:03am
From 7 women and 9 men = "16 people choose 5" for a committee, there are "16 choose 5" ways, or

(16,5)=C(16,5)=16!/(5!(16-5)!) ways

Out of these, "9 choose 5" ways include no woman, and must be subtracted.

So the number of ways of selecting a committee of 5 from 9 men and 7 women with at least one woman is

"16 choose 5" - "9 choose 5".

## Answer this Question

## Related Questions

- math - In how many ways can a committee of five people be selected from seven ...
- math prob - A committee of 5 people is selected from a group of 7 men and 9 ...
- statistics - A committee consists of five men and four women. Two people are ...
- statistics permutations and combinations - Selecting a committee: There are 7 ...
- maths - How can I select a committee of 5 people out of 10 men and 8 women. ...
- math - a committee of 5 people is to be selected from a group of 6 men and 9 ...
- gr12 math - froma group of 6 ladies and 4 men, determine in how many ways a ...
- math - from a group of women and 4 men, determine in how many ways a committee ...
- Math - A certain club consists of 5 men and 6 women. a) How many ways are there ...
- 12 math - a club consists of 25 married couples. determine how many committee of...