Posted by Fakaapo on Monday, April 18, 2011 at 5:20am.
From 7 women and 9 men = "16 people choose 5" for a committee, there are "16 choose 5" ways, or
(16,5)=C(16,5)=16!/(5!(16-5)!) ways
Out of these, "9 choose 5" ways include no woman, and must be subtracted.
So the number of ways of selecting a committee of 5 from 9 men and 7 women with at least one woman is
"16 choose 5" - "9 choose 5".
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