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Algerbra

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3(y-3)=(x+6)squared how do you find the vertex and foci,directrix

  • Algerbra - ,

    3(Y-3) = (X+6)^2,
    3Y-9 = X^2+12X+36,
    3Y = X^2+12X+36+9,
    3Y = X^2+12X+45,
    Y = X^2/3+4X+15,

    h = -b/2a = -4/(2/3) = -12/2 = -6.

    k=Yv = (-6)^2/3+4*(-6)+15 = 12-24+15 = 3.

    V(h,k)= V(-6,3).

    F(-6,Y2)

    V(-6,3)

    D(-6,Y1)

    3-Y1 = 1/4a = 1/(4/3) = 3/4,
    -Y1 = 3/4 -12/4 = -9/4,
    Y1 = 9/4.

    Y2-3 = 1/4a = 1/(4/3) = 3/4,
    Y2 = 3/4+12/4 = 15/4.

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