Algerbra
posted by Mario on .
3(y3)=(x+6)squared how do you find the vertex and foci,directrix

3(Y3) = (X+6)^2,
3Y9 = X^2+12X+36,
3Y = X^2+12X+36+9,
3Y = X^2+12X+45,
Y = X^2/3+4X+15,
h = b/2a = 4/(2/3) = 12/2 = 6.
k=Yv = (6)^2/3+4*(6)+15 = 1224+15 = 3.
V(h,k)= V(6,3).
F(6,Y2)
V(6,3)
D(6,Y1)
3Y1 = 1/4a = 1/(4/3) = 3/4,
Y1 = 3/4 12/4 = 9/4,
Y1 = 9/4.
Y23 = 1/4a = 1/(4/3) = 3/4,
Y2 = 3/4+12/4 = 15/4.