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September 17, 2014

September 17, 2014

Posted by **ali** on Sunday, April 17, 2011 at 11:32pm.

- pre cal -
**Bosnian**, Monday, April 18, 2011 at 6:55amsin(theta)=1/5

cos(theta)=sqroot[1-sin(teta)^2]

cos(theta)=sqroot[1-(1/5)^2]

cos(theta)=sqroot(1-1/25)

cos(theta)=sqroot(25/25-1/25)

cos(theta)=sqroot(24/25)

cos(theta)=sqroot(6*4/25)

cos(theta)=sqroot(6*2^2/5^2)

cos(theta)=(2/5)*sqroot(6)

sin(2theta)=2*sin(theta)*cos(theta)

sin(2theta)=2*(1/5)*(2/5)sqroot(6)

sin(2theta)=(4/25)*sqroot(6)

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