Sunday
November 23, 2014

Homework Help: Calculus

Posted by Janet on Sunday, April 17, 2011 at 11:29pm.

Find any absolute maximum and minimum and local maximum and minimum for the function f(x)=x^3-4x+5 on the interval [0,5). Make sure to prove that these points are max/min values.

THis is what I did.

f'(x)=3x^2-4=0
x= +/- 2/sqrt3
-2/sqrt3 is outside of interval so just use 2/sqrt3 (I think that's considered a critical point)

f(2/sqrt3)= 1.921
f(0) = 5
f(5)=110

I'm not sure what to do with all these numbers. I think since 1.921 is the smallest of the numbers that 2/sqrt 3 is the minimum, but is it the local or absolute.
It looks like 5 is the max, but again local or absolute and can I really include this to be max since it isn't even included in the interval [0,5)

Can someone give me some guidance or show me some steps to solve this.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...
Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...
Calculus - Find any absolute max/min and local max/min for the function f(x)=x^3...
Calculus - Find the absolute maximum and absolute minimum values of the function...
calculus - 2) Let g(s)= t(4−t)^1/2 on the interval [0,2]. Find the ...
Math - I need an expiation on a math concept, because I know the right answer, I...
calculus - a function has a local maximum at x=-2 and x=6 and a local minimum at...
Absolute Extrema - Find the minimum and maximum values of the function f(x)= 2/3...
Calculus - Let f(t)=t\sqrt{4-t} on the interval [-1,3]. Find the absolute ...
calculus - Let g(x)=(4x)/(x^2+1) on the interval [-4,0]. Find the absolute ...

Search
Members