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September 18, 2014

September 18, 2014

Posted by **Jay** on Sunday, April 17, 2011 at 11:09pm.

Gasoline usage for compact cars in Canada is a normal distribution with a mean of 33.3 km/l and with standard deviation of 7.3 km/L. Round your answers to one decimal place.

a) What percentage of compact cars obtains 20km/L or LESS?

z= x-mean/standard deviation

= 20-33.3/7.3

= 1.82 Km/L

(find percent through z-score table)

which becomes 0.0344 x 100

= 3.4 %

b) What percentage of compact cars obtains MORE than 40 km/L

z=40-33.3/7.3

= 0.92 km/L = 0.8212

= 1 - 0.8212

= 0.1788 x 100

= 17.9%

Question is, for question b, is it 1-0.8212 or 100-0.8212?

- Math -
**PsyDAG**, Monday, April 18, 2011 at 3:52pma) Z = -1.82 ≠ 1.82 Km/L

Otherwise it is correct.

b) Z = .92 (not km/L)

Don't need to subtract from one (which is correct of the two), if you use column for proportion in*smaller*area in the table.

Final answer correct.

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