Posted by anonymous on Sunday, April 17, 2011 at 10:22pm.
1) There is a solution to x = (y5)^2 and x = (y 5 )^2 + 7
a) true
b) false
2) There is no real solution to y = 1 and y = x^2 + 9
a) true
b) false
3) the vertex of the graph of y = 3(x+ 9)^2 + 5 is a minimum value ?
a) true
b) false
4)find the center and radius of the circle with the given equation x^2 + y^2 + 6y = 50 14x
5) sketch the graph of y = (x+2)^2  1
6) sketch the graph of 9x^2 + 4y^2 = 36
7) sketch the graph of (y  1)^2 /9  (x+2)^2 /4 = 1
8) solve the system, x^2/16 + y^2/4 less than or equal to 1 and y > 1x/2 2
Can some one assist me with these ? I'm lost here,

Algebra II  Henry, Monday, April 18, 2011 at 6:10pm
1 False.
2. True.
3. True.
4. X^2 + Y^2 + 6Y =  50  14X,
Complete the square:
X^2+14X+(14/2)^2+Y^2+6Y+(6/2)^2=50,
X^2+14X+49+Y^2+6Y+9 = 50+49+9,
X^2+14X+49+Y^2+6Y+9 = 8,
Factor the perfect squares:
(X+7)^2+(Y+3)^2 = 8 = r^2,
C(7,3).
r = sqrt8 = 2.83
5. Y = (X+2)^21.
Graph the given Eq using the selected points listed below:
(4,3), (3,0), V(2,1), (1,0),(0,3).
6. 9X^2+4Y^2 = 36,
Divide both sides by 36:
X^2/4+Y^2/9 = 1, YElipse.
Graph the elipse using the points listed below:
(2,0), (2,0), (0,3), (0,3).
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