Posted by ashley -- on Sunday, April 17, 2011 at 7:15pm.
when one end is open, the pipe is 1/4 *nodd wavelength long.
f*lambda=v
f*4/n * .2=v
solve for f. given, n=1,3,5
both ends open, the pipe is n/2 lambda long, n =1,2,3,
f*2/n
(A) When only one end is open, it is a 'closed' pipe and so we use
Where fn = frequency of nth harmonic (Hz)
n = harmonic number
v = speed of sound inside the pipe (m/s)
L = length of pipe closed at one end (m)
Plugging in the values and solving, we get f1 = 428.75 Hz
f3 = 1286.25 Hz
f5 = 2143.75 Hz
(B) When both ends are open, it is an 'open' pipe and so we use
Plugging in the values and solving, we get f1 = 857.5 Hz
f2 = 1715 Hz
f3= 2572.5 Hz
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