Math(Please help)
posted by Hannah on .
f(x,y)= 10x^1/3 y^2/3
Compute (27,64)
so 10(27)^1/3 * (64)^2/3
10 * (27)^1/3 * (64)^2/3
I know that the answer is 480 but I am having a hard time calculating 27^1/3 and 64^2/3.

cube root of 27? 3
cube root of 64, then squared?
64=4*4*4 so the answer is 16
10*3*16=... 
Oh, I see. Thank you