C6H12O6= 2C2H5OH + 2CO2 WITH 1KG OF GLUCOSE, WHAT IS THE MAX AMOUNT OF ETHANOL (INGRAMS OR LITERS) THAT CAN BE OBTAINED BY THE PROCESS. (DENSITY OF ETHANOL= 0.789g/ml.

From one mole of glucose, you get two moles of ethanol.

so the question is, how many moles of glucose do you have in 1000grams?

molesglucose: 1000/molmassGlucose

then molesethanol: twice that. Convert that to gramsEthanol by multiplying it by the mole mass of ethanol.

To find the maximum amount of ethanol that can be obtained from 1 kg of glucose, we need to calculate the number of moles of glucose and then use the balanced chemical equation to determine the moles of ethanol produced. Finally, we can convert the moles of ethanol to grams or liters using the density of ethanol.

Step 1: Calculate the number of moles of glucose
The molar mass of glucose (C6H12O6) is:
(6 × atomic mass of carbon) + (12 × atomic mass of hydrogen) + (6 × atomic mass of oxygen)

Using the atomic masses from the periodic table:
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of hydrogen (H) = 1.01 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol

The calculation becomes:
(6 × 12.01) + (12 × 1.01) + (6 × 16.00) = 180.18 g/mol

Now, divide the mass of glucose (1 kg) by its molar mass to get moles:
Number of moles = 1000 g / 180.18 g/mol ≈ 5.55 moles

Step 2: Use the balanced chemical equation to determine moles of ethanol produced
According to the balanced equation:
1 mole of glucose (C6H12O6) produces 2 moles of ethanol (C2H5OH)

Therefore, the number of moles of ethanol can be calculated as:
Number of moles of ethanol = 5.55 moles × 2 = 11.10 moles

Step 3: Convert moles of ethanol to grams or liters
To convert moles of ethanol to grams, we'll multiply the number of moles by its molar mass:
Molar mass of ethanol (C2H5OH) = (2 × atomic mass of carbon) + (6 × atomic mass of hydrogen) + (1 × atomic mass of oxygen)

Using the atomic masses:
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of hydrogen (H) = 1.01 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol

The molar mass of ethanol is:
(2 × 12.01) + (6 × 1.01) + 16.00 = 46.07 g/mol

Now, multiply the number of moles of ethanol by its molar mass to find the amount in grams:
Amount of ethanol in grams = 11.10 moles × 46.07 g/mol ≈ 511.77 grams

To convert grams to milliliters (ml) of ethanol, we need to divide by the density of ethanol:
Amount of ethanol in milliliters (ml) = 511.77 g / 0.789 g/ml ≈ 648.81 ml

Therefore, the maximum amount of ethanol that can be obtained from 1 kg of glucose is approximately 511.77 grams or 648.81 milliliters.