Posted by BreAnna on Saturday, April 16, 2011 at 11:21pm.
When the order does not matter, the number ways of choosing the lottery can be calculated using combinations, or C(n,r), read as "n chose r". C(n,r) is defined as n!/(r!(n-r)!), similar to the evaluation problem of your other post.
So in the case of the lottery problem, n=40, r=6, and order does not matter. So "40 choose 6" gives the answer.
Evaluate "40 choose 6" the same way as the other problem:
40!/(6!(40-6)!)=....
Read the following link for more detailed information:
http://en.wikipedia.org/wiki/Combination
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