Posted by Anna on Saturday, April 16, 2011 at 6:33pm.
H2(g) ==> 2H^+(aq) + 2e..Eo = 0 v
I2(s) + 2e ==> 2I^-(aq)..Eo = +0.535 v
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H2(g) + I2(s) ==> 2H^+(aq) + 2I^-(aq)
Ecell as written = 0.535 v (0 + 0.535 = 0.535 v) and it is spontaneous since Ecell is positive. I have used each equation AS WRITTEN and I have not rearranged either half reaction; however, I think the problem contradicts itself in the first sentence. If I am to use standard reduction potentials then I must rearrange one of the half cells and that is forbidden in the problem. Anyway, you have the cell reaction as written, the cell potential as written, and that it is spontaneous as written. I hope this helps. The others are done the same way.
Thank you so so much!!!
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