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September 1, 2014

September 1, 2014

Posted by **John** on Saturday, April 16, 2011 at 5:39pm.

- trig -
**MathMate**, Saturday, April 16, 2011 at 7:12pmGiven ΔPDJ,

PJ=132 miles

PD=72 miles

DJ=84 miles

Triangle (angles) can be solved using the cosine rule, since all sides are known.

Let ∠PDJ = θ

Then

cos(θ) = (PD^sup2;+DJ²-PJ²)/(2PD*DJ)

Can you take it from here?

- trig -
**maria**, Sunday, May 4, 2014 at 1:09am115.4

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