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Posted by on Saturday, April 16, 2011 at 3:09pm.

A man of mass 80 kg and density 970 kg/m3 stands in a shallow pool with 31% of the volume of his body below water. Calculate the normal force the bottom of the pool exerts on his feet. (Take the positive direction to be up. Indicate the direction with the sign of your answer.)

  • Physics (please help!!!!) - , Saturday, April 16, 2011 at 5:42pm

    density of water = 1000

    volume of man = 80 kg / 970kg/m^3 = .0825m^3

    .31*.0825 = .0256 m^3

    buoyant force up on man = .0256*1000*9.81 = 251 Newtons

    weight of man = 80*9.81 = 785 Newtons

    weight - buoyancy = 785 -251 = 534 N

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