PRECALCULUS HELP PLEASE!
posted by YOSHI .
convert the polar equation to rectangular form.
1.) r sec(theta) = 3
2.) r = 4 cos(theta)  4 sin(theta)
convert from rectangular equation to polar form.
1.) x^2 + (y1)^2 = 1
2.) (x1)^2 + (y+4)^2 = 17

1)r=3cos(theta)
r^2=3rcos(theta)
x^2+y^2=3x
2)r=4cos(theta)4sin(theta)
r^2=4rcos(theta)4rsin(theta)
x^2+y^2=4x4y
x^24x +y^2+4y =0
x^24x+4+y^2+4y+4=4+4
(x2)^2 +(y+2)^2=8
1)x^2+(y1)^2=1
x^2+y^22y+1=1
x^2+y^2=2y
r^2=2rsin(theta)
r=2sin(theta)
2)(x1)^2+(y+4)^2=17
x^22x+1+y^2+8y+16=17
x^2+y^2=2x8y
r^2=2rcos(theta)8rsin(theta)
r=2cos(theta)8sin(theta) 
thank you soooooooooo much