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December 17, 2014

December 17, 2014

Posted by **YOSHI** on Saturday, April 16, 2011 at 1:26am.

1.) r sec(theta) = 3

2.) r = 4 cos(theta) - 4 sin(theta)

convert from rectangular equation to polar form.

1.) x^2 + (y-1)^2 = 1

2.) (x-1)^2 + (y+4)^2 = 17

- PRECALCULUS HELP PLEASE! -
**Mgraph**, Saturday, April 16, 2011 at 6:27am1)r=3cos(theta)

r^2=3rcos(theta)

x^2+y^2=3x

2)r=4cos(theta)-4sin(theta)

r^2=4rcos(theta)-4rsin(theta)

x^2+y^2=4x-4y

x^2-4x +y^2+4y =0

x^2-4x+4+y^2+4y+4=4+4

(x-2)^2 +(y+2)^2=8

1)x^2+(y-1)^2=1

x^2+y^2-2y+1=1

x^2+y^2=2y

r^2=2rsin(theta)

r=2sin(theta)

2)(x-1)^2+(y+4)^2=17

x^2-2x+1+y^2+8y+16=17

x^2+y^2=2x-8y

r^2=2rcos(theta)-8rsin(theta)

r=2cos(theta)-8sin(theta)

- PRECALCULUS HELP PLEASE! -
**YOSHI**, Saturday, April 16, 2011 at 1:07pmthank you soooooooooo much

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