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March 30, 2015

March 30, 2015

Posted by **kesha** on Friday, April 15, 2011 at 7:57pm.

- statistics -
**PsyDAG**, Saturday, April 16, 2011 at 11:36amdf = 25-1 = 24

For P = .05, with 24 df, you need to have difference between means ± 2.064(SEdiff)

t = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1) or to make it easier, you can use n

SD = √(variance)

I'll leave the calculation and explanation to you.

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