Posted by kesha on Friday, April 15, 2011 at 7:57pm.
df = 25-1 = 24
For P = .05, with 24 df, you need to have difference between means ± 2.064(SEdiff)
t = (mean1 - mean2)/standard error (SE) of difference between means
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√(n-1) or to make it easier, you can use n
SD = √(variance)
I'll leave the calculation and explanation to you.
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