Consider a jet of water striking a vertical wall horizontally a speed of v. After hitting the wall, the water moves along the wall. If the area of cross-section of the water jet is S, Find the force that it applies on the wall. Take the mass density of water to be p.
To find the force that the water jet applies on the wall, we can use Newton's second law, which states that force (F) is equal to mass (m) times acceleration (a).
In this case, the mass of the water is given by its density (p) multiplied by its volume (V). The volume of the water can be obtained by multiplying the cross-sectional area (S) by the distance the water travels along the wall (d).
To find the acceleration, we need to consider the change in velocity of the water. Initially, the water is moving horizontally with a speed of v. After hitting the wall, the water moves along the wall, with its velocity reducing to zero due to friction. Therefore, the change in velocity (Δv) is equal to v.
Now we can calculate the force exerted by the water on the wall using the following steps:
1. Calculate the volume of water: V = S * d
2. Calculate the mass of water: m = p * V = p * S * d
3. Calculate the acceleration of the water: a = Δv / Δt, where Δt is the time taken by the water to stop. Since the water moves from v to 0, Δv = v - 0 = v. The time taken to stop depends on the friction between the water and the wall, and additional information is required to calculate it.
4. Finally, calculate the force exerted by the water on the wall using Newton's second law: F = m * a
Please note that without the specific value of Δt or additional information, we are unable to determine the exact force exerted by the water on the wall.