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October 20, 2014

October 20, 2014

Posted by **Margret** on Friday, April 15, 2011 at 10:07am.

- Algerbra -
**Jai**, Friday, April 15, 2011 at 10:17am(x+2)(x+4) = 30 + x

first we expand the left side of the equation,, multiplying them,

x^2 + 2x + 4x + 8 = 30 + x

then we combine similar terms and make the right side of equation equal to zero (since it's quadratic equation) :

x^2 + 6x + 8 - 30 - x = 0

x^2 + 5x - 22 = 0

now, since it's not factorable, we use quadratic formula

x = [-b +- sqrt(b^2 - 4ac)]/(2a)

note: +- is plus or minus

substituting,

x = [-5 +- sqrt(5^2 - 4(1)(-22))]/(2*1)

x = [-5 +- sqrt(25 +88)]/2

x = [-5 +- sqrt(113)]/2

separating this into plus and minus:

x = [-5 + sqrt(113)]/2 ; and

x = [-5 - sqrt(113)]/2

hope this helps~ :)

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