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Determine the pH of 263 ml of solution which has [NH 4I] = 0.300 M. Kb = 1.74 × 10-5 for NH3(aq)

  • Chemistry - ,

    I managed to get it :)
    though for others who might be looking to solve this for their practice questions

    Convert Kb to Ka
    Ka = kw/Kb

    then just use an ice table with Ka=x^2/ 0.300M-x (x is small)
    and just -log[H3O+)

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