Posted by Akash on Thursday, April 14, 2011 at 1:03pm.
Even you subject is "Quadratic Equations", the problem you submitted is a cubic equation, and there appears to be no typo.
We will solve the cubic as it is posted.
x^3-3x^2+4=0
We note that the coefficients add up to zero if we reverse the sign of x^3, i.e. (-1)-3+4=0
This indicates that x=-1 is a zero.
Use long polynomial division to reduce the equation to:
(x^3-3x^2+4)/(x+1)=x²-4x+4
which is a quadratic equation.
We can solve by factorization:
x²-4x+4 = 0
(x-2)²=0
Therefore x=-1 or x=2(multiplicity=2), i.e. x=-1, x=2 or x=2.
any other easy method
I do not see an easier method except factoring trial and error. For this particular problem, you will probably get the answers by trial factoring quite easily.
Remember that this is a cubic equation, which actually has a solution formula more complicated than the above.
There is also the Newton-Ralphson approximation method by iterations.
The above methods (factoring, long division, quadratic equation) do not introduce any algebraic operation that is beyond secondary school level.
N+ ( n+2)=16
N+ ( n+2)=16
Related Questions
Algebra - Please help me to solve these two equations step by step. They are ...
algebra 1 - ELEMENTARY ALGEBRA #3 Page 23 Chapter 3 Lesson 3.02 Solving Multi-...
Simple Maths - Suppose student gets 30 marks out of 70 so how much will he get ...
Algebra 2 - I need to know how to solve quadratic equations by factoring. Can ...
Algebra help - f(x)=x^3-4x^2-x+4 How do I find the x-intercept for this? This is...
pre algebra - solve the equation step by step.list each step along with the ...
algebra 2 - can anyone please help me solve this step by step by using the ...
chemistry - What is the percent ionization of a 1.38 mol/L weak acid if its Ka...
math - My problem I have involves a method that requires using the quadratic ...
Pre-Cal - Hi, can someone please solve this step-by-step for me? I really don&#...
For Further Reading
