CH3CO2H: 0.109M & 20ml
NaOH : 0.109M& 10ml
Buffer Problem, when I solve it the ratio becomes the same and the pH is the same as the pka, is that right?
Buffer L - SraJMcGin, Thursday, April 14, 2011 at 11:38am
See if any of the following sites will help:
Buffer L - DrBob222, Thursday, April 14, 2011 at 12:31pm
Yes, pH = pKa. WHY? because the log(base)/(acid) = 0
pH = pKa + log(base)/(acid)
pH = pKa + log (0.109/0.010)/(0.109/0.010)
pH = pKa + log (1)
pH = pKa + 0 = pKa.