Posted by **sahmit** on Thursday, April 14, 2011 at 4:02am.

solve the equation

sin(3x) + (1/2) = 2cos^2(x)

for X to be between 0 and 360

- Math -
**MathMate**, Thursday, April 14, 2011 at 10:34am
Use the relation

cos²(x)=1-sin²(x)

to convert the equation to a quadratic in sin(x).

Solve for the value of sin(x), say s1 and s2 and reject any impossible roots such as |s|>1.

For the remaining root(s), solve for

sin(θ)=s. There should always be two values of θ (0≤ θ<360°)for each valid value of s, where -1≤s≤+1.

If you need further help, post.

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