Posted by sahmit on Thursday, April 14, 2011 at 4:02am.
Use the relation
cos²(x)=1-sin²(x)
to convert the equation to a quadratic in sin(x).
Solve for the value of sin(x), say s1 and s2 and reject any impossible roots such as |s|>1.
For the remaining root(s), solve for
sin(θ)=s. There should always be two values of θ (0≤ θ<360°)for each valid value of s, where -1≤s≤+1.
If you need further help, post.
Related Questions
Math - Solving for Trig Equations - Solve the following equation for 0 less than...
math - Solve the following equations giving any roots in terms of pi in the...
trig - I dont understand this. can you please tell how you got each answer? ...
trig - Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0
Math, derivatives - f(x) = x² + 2Cos²x, find f ' (x) a) 2(x+cos x...
Maths - solve the following eq. [0<=x<=360] 2cos(3x-72)=1
Math - Solving Trig Equations - What am I doing wrong? Equation: sin2x = 2cos2x ...
precal - when i do the quadratic equation i get -17 plus or minus the square ...
Trigonometry - Solve the equation for all values of x. -2cos²x-sin x+1=0, ...
Math - Solving Trig Equations - Solve each equation for 0 is less than and equal...
For Further Reading