Tuesday

October 21, 2014

October 21, 2014

Posted by **sahmit** on Thursday, April 14, 2011 at 4:02am.

sin(3x) + (1/2) = 2cos^2(x)

for X to be between 0 and 360

- Math -
**MathMate**, Thursday, April 14, 2011 at 10:34amUse the relation

cos²(x)=1-sin²(x)

to convert the equation to a quadratic in sin(x).

Solve for the value of sin(x), say s1 and s2 and reject any impossible roots such as |s|>1.

For the remaining root(s), solve for

sin(θ)=s. There should always be two values of θ (0≤ θ<360°)for each valid value of s, where -1≤s≤+1.

If you need further help, post.

**Answer this Question**

**Related Questions**

Precalculus - Solve the equation in the indicated domain. 1. 2cos^2 x-5cos x +2=...

PRECALCULUS - Solve the equation in the indicated domain. 1. 2cos^2 x-5cos x +2=...

Math - Solving for Trig Equations - Solve the following equation for 0 less than...

MathsSs triG - Consider sin(x-360)sin(90-x)tan(-x)/cos(90+x) 1.A.SIMPLIFY sin(x-...

Math, derivatives - f(x) = x² + 2Cos²x, find f ' (x) a) 2(x+cos x) b) x - sin x ...

math - Solve the following equations giving any roots in terms of pi in the...

trig - Solve the equation on the interval [0,360) cos^2t+2cos(t)+1=0

Math - Solving Trig Equations - What am I doing wrong? Equation: sin2x = 2cos2x ...

Calc - Which functions of x and y in terms of time t can be derived from this ...

math - solve each equation for 0=/<x=/<2pi sin^2x + 5sinx + 6 = 0? how do ...