(x-3)^2
I'm going to start you off on this one, but you already asked one a lot like this, and we are not going to do your homework for you.
(x-3)(x-3)
x(x) + x(-3) + x(-3) + -3(-3)
You should be able to figure it out from there.
yeah sorry but very bad at math this is wat i got
x^2 +3x-3x+9
ther suposed to be 3 terms but i got 4
y did u do what u did ?
the x(x)....
I was just writing it out, it's the same thing you did when you got x^2, I was just showing multiplying the two x's. And it it three terms when you add like terms together. I'll continue with what I did before.
x^2 -3x -3x +9. You basically did the same thing, only both 3x should be -3x. You can add the -3x and -3x together to get -6x. So now your final answer would be
x^2-6x+9
thanks so much lol i was geting confused at the 3x and the -3x cuz i thought when u add them it wud b like -6x^2 u no what i meen? but yeah thanks that realy helpd me alot ;)
To simplify the expression (x-3)^2, you need to apply the rule of exponents.
The exponent 2 means that you need to multiply the base (x-3) by itself.
So, you can rewrite (x-3)^2 as (x-3)(x-3).
To multiply these two binomials, you can use the FOIL method, which stands for First, Outer, Inner, Last.
First, you multiply the first terms of each binomial:
(x * x) = x^2
Outer, you multiply the outer terms of each binomial:
(x * -3) = -3x
Inner, you multiply the inner terms of each binomial:
(-3 * x) = -3x
Last, you multiply the last terms of each binomial:
(-3 * -3) = 9
Now that you have the four products, you can combine them by adding or subtracting them.
Putting it all together,
(x-3)(x-3) = x^2 - 3x - 3x + 9.
Combining like terms,
(x-3)^2 = x^2 - 6x + 9.
So, the simplified version of (x-3)^2 is x^2 - 6x + 9.