Homework Help: Physics 3

Posted by Ziera on Wednesday, April 13, 2011 at 1:55pm.

A 2.3-keV proton is moving horizontally and passes perpendicular to the Earth’s magnetic field at a location where the field magnitude is 52.0 T.

i) Determine the magnetic force on the proton?

ii) Find the ratio of this force to the gravitation force on the proton?

iii) What energy of proton would be needed to make the magnetic and gravitational forces to be equal?

iv) What direction proton would be, to keep the motion in horizontal?

Physics 3 - bobpursley, Wednesday, April 13, 2011 at 2:26pm
change the 2.3keV to velocity.

Then, force magnetic=Bq*veloctiy

I am uncertain what difficulty you are having here.

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