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December 20, 2014

December 20, 2014

Posted by **melissa** on Wednesday, April 13, 2011 at 11:25am.

- geometry -
**MathMate**, Wednesday, April 13, 2011 at 2:10pmA polygon of n sides can have n-1 diagonal from each vertex. From n vertices, the polygon can have n(n-1)/2 diagonals. The number has to be divided by 2 because we have counted the diagonal from both sides.

So using the formula

d(n)=n(n-1)/2

you can find n.

Hint: n is between 5 and 15.

- geometry -
**Malcolm**, Monday, April 25, 2011 at 3:33pmDo me so hard MM!

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