Posted by Anonymous on Wednesday, April 13, 2011 at 9:47am.
he world population at the beginning of 1990 was 5.3 billion. Assume that the population continues to grow at the rate of approximately 2%/year and find the function Q(t) that expresses the world population (in billions) as a function of time t (in years), with t = 0 corresponding to the beginning of 1990. (Round your answers to two decimal places.)
(a) If the world population continues to grow at approximately 2%/year, find the length of time t0 required for the population to double in size.
t0 = yr
(b) Using the time t0 found in part (a), what would be the world population if the growth rate were reduced to 1.6%/yr?
billion people

Math  Henry, Friday, April 15, 2011 at 11:05pm
Q(t) = 5.3 + 0.02*5.3t,
Q(t) = 5.3 + 0.106t.
a. Q(t) = 5.3 + 0.106t = 10.6 Billion,
5.3 + 0.106t = 10.6,
0.106t = 10.6  5.3 = 5.3,
t = 50 years.
b. Q(t) = 5.3 + 0.016t*5.3,
Q(t) = 5.3 + 0.0848t.
Q(t) = 5.3 + 0.0848*50 = 9.54 Billion.

Math  Ruvinka, Tuesday, December 11, 2012 at 6:34pm
part a is incorrect, the proper answer is:
Q(t)=Qoe^kt
Q(t)= 5.3e^0.02t
2=e^0.02t
ln2=0.02t
t=34.6yr
Answer This Question
Related Questions
 Applied Calculus  The world population at the beginning of 1990 was 5.3 billion...
 Algebra  Wk 6 Sec 12.7 #24 World population growth In 2008 the world population...
 maths  The population of the world in 1987 was 5 billion and the annual growth ...
 maths  The population of the world in 1987 was 5 billion and the annual growth ...
 math  UGH! The human population of the world is over 6 billion. The increase of...
 human life  The human population of the world is over 6 billion. The increase ...
 math 12  The world's population is 1970 was about 3.6 billion. If the ...
 Math  The population of the Earth is approximately 6 billion people and is ...
 Calculus  for population in billions, where t is years since 1990: N(t) = 41/1+...
 Calculus  According to the US Census, the world population P, in billions, is ...
More Related Questions