Posted by rooftops on Wednesday, April 13, 2011 at 7:42am.
Your posts have been removed because of your "homework dumping" -- a string of posts in quick succession with absolutely no sign that you have given any thought to anything.
Once you write up YOUR THOUGHTS, please re-post, and someone here will be happy to comment.
NH3 + H2O ==> NH4^+ + OH^
Kb = (NH4^+)(OH^-)/(NH3)
Convert pH to pOH, then to (OH^-), substitute into Kb. Also substitute into Kb what you want the (NH4^+) to be and solve for (NH3).
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