Homework Help: Physics

Posted by Sam on Wednesday, April 13, 2011 at 12:05am.

A 1.0 KΩ resistor is connected in series with a 10.0 mH inductor, a 30.0 V battery, and an open switch. At time t=0, the switch is suddenly closed. What are the voltage drops VR and VL 20.00 盜 after the switch is closed?

Physics - Henry, Thursday, April 14, 2011 at 6:24pm
VL = Vap / e^t/T,

T=L/R=10*10^-3h/1*10^-3Ohms=10*10^-6s.

t/T = 20*10^-6s / 10*10^-6s = 2.

VL = 30 / e^2 4.06 volts.

VR = 30 - 4.06 = 25.94 volts.

Answer this Question

Related Questions

physics - A 9.2V battery is connected in series with a 33mH inductor, a 190 Ohms...
Physics!!! - A 24-V battery is connected in series with a resistor and an ...
physics please help!! - 1. A 26.0-Ω resistor, a 12.0-µF capacitor...
Physics - In a series circuit, a generator (1400 Hz, 12.0 V) is connected to a ...
Physics - In a series circuit, a generator (1400 Hz, 12.0 V) is connected to a ...
College Physics - A 22 μF capacitor and a 5.20 mH inductor are ...
physics - The current in a 51 resistor is 0.14 A. This resistor is in series ...
physics so confused - 1. A 26.0-Ω resistor, a 12.0-µF capacitor, ...
Physics - A 200-Ù resistor, 40.0-mH inductor and a 2.00-ìF ...
physics - a 2 uF capacitor is connected in series with a 1.2 M ohms resistor and...

For Further Reading

First Name:
School Subject:
Answer: