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Posted by **brooke** on Tuesday, April 12, 2011 at 9:34pm.

equation: 5(3r-7)+r=3(r-3)

15r-35+r=3r-9

15r+r-3r=-35-9

13r/13 = -44/13

- grade nine math -
**bobpursley**, Tuesday, April 12, 2011 at 9:46pmno. the third line should read

15r+r-3r=35-9

- grade nine math -
**Jai**, Tuesday, April 12, 2011 at 9:47pmfrom the 2nd line, when -35 is transposed to other side,

15r - 35 + r = 3r - 9

15r + r - 3r = 35 - 9

...it must be positive 35. you forgot to change its sign.

- grade nine math -
**brooke**, Tuesday, April 12, 2011 at 9:49pmOh so you are saying that the 35 should be a positive instead of a negative. Is that correct!!So the answer for r is 2. Thanks I think I get it.

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