is the answer to my equation right?
equation: 5(3r-7)+r=3(r-3)
15r-35+r=3r-9
15r+r-3r=-35-9
13r/13 = -44/13
no. the third line should read
15r+r-3r=35-9
from the 2nd line, when -35 is transposed to other side,
15r - 35 + r = 3r - 9
15r + r - 3r = 35 - 9
...it must be positive 35. you forgot to change its sign.
Oh so you are saying that the 35 should be a positive instead of a negative. Is that correct!!So the answer for r is 2. Thanks I think I get it.
To verify if the answer to your equation is correct, let's go through the steps of solving it together:
1. Start with the given equation: 5(3r-7) + r = 3(r-3)
2. Simplify each side of the equation using the distributive property:
- On the left side, distribute 5 to both terms inside the parentheses: 15r - 35 + r = 3(r - 3)
- On the right side, distribute 3 to both terms inside the parentheses: 15r - 35 + r = 3r - 9
3. Combine like terms on each side:
- On the left side, combine the 15r and r terms: 15r + r - 35 = 3r - 9
- On the right side, there are no like terms to combine: 15r + r - 35 = 3r - 9
- Simplify further: 16r - 35 = 3r - 9
4. Get all the r terms on one side of the equation and all the constant terms on the other side:
- Subtract 3r from both sides: 16r - 3r - 35 = 3r - 3r - 9
- Simplify further: 13r - 35 = -9
5. Move the constant term (-35) to the other side by adding 35 to both sides:
- Add 35 to both sides: 13r - 35 + 35 = -9 + 35
- Simplify further: 13r = 26
6. Finally, solve for r by dividing both sides of the equation by 13:
- Divide both sides by 13: 13r/13 = 26/13
- Simplify further: r = 2
So, the answer to your equation is r = 2.