Posted by cheryl on .
If a high schol base ball player average pitching speed is 50 ft. in .63 sec. and the average pitch drops 9 mph over 10 ft.
What is the player's pitching speed in 50 ft. equivalence(rounded to the tenth).
college math 120 -
50 ft per .63 sec = 79.3651 ft per sec
79.3651 ft per sec = 54.112568 mph
every 10 ft the speed drops 9 mph, so 54.112568 mph - (5 x 9) = 9.112568 mph
I'm not sure I understood the question completely, but I think this is the right answer.