Posted by **cheryl** on Tuesday, April 12, 2011 at 7:13pm.

If a high schol base ball player average pitching speed is 50 ft. in .63 sec. and the average pitch drops 9 mph over 10 ft.

What is the player's pitching speed in 50 ft. equivalence(rounded to the tenth).

- college math 120 -
**Aaron**, Saturday, October 22, 2011 at 5:15pm
50 ft per .63 sec = 79.3651 ft per sec

79.3651 ft per sec = 54.112568 mph

every 10 ft the speed drops 9 mph, so 54.112568 mph - (5 x 9) = 9.112568 mph

I'm not sure I understood the question completely, but I think this is the right answer.

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