a bike is 25% efficient in converting energy of the bicyclist to mechanical energy. If a cyclist is travelling along a pathway at a constant speed of 5.8 m/s for 3600 s, and the average resistance is 22 N, how much mass does she lose assuming 1 kg is lost for each 2.9 x 10^7 J of energy she uses?

The bike does 22*5.8*3600 joules work.

She does 4 times that amount of energy, or
4*22*5.8*3600 joules.

Weightlost? 4*22*5.8*3600/2.9E7= not much.

Thank you so much!

To calculate the mass lost by the cyclist, we need to determine the energy used during the cycling activity and then convert it to mass using the given conversion factor.

First, let's find the total energy used by the cyclist. We know that the average resistance is 22 N, and the cyclist travels at a constant speed of 5.8 m/s for 3600 seconds.

The work done against resistance is given by the equation:

Work = Force × Distance

Since the speed is constant, we can use the equation:

Work = Force × Speed × Time

Thus, the work done against resistance is:

Work = 22 N × 5.8 m/s × 3600 s

Now, we can calculate the energy used by multiplying the work done by efficiency:

Energy Used = Work × Efficiency

Given that the bike is 25% efficient, we have:

Energy Used = Work × 0.25

Substituting the value of work, we get:

Energy Used = (22 N × 5.8 m/s × 3600 s) × 0.25

Now we can calculate the energy used:

Energy Used = 22 N × 5.8 m/s × 3600 s × 0.25

Next, we need to convert the energy used to mass, using the conversion factor of 1 kg lost per 2.9 × 10^7 J of energy used.

Mass Lost = Energy Used / Conversion Factor

Substituting the values we calculated, we have:

Mass Lost = (22 N × 5.8 m/s × 3600 s × 0.25) / (2.9 × 10^7 J)

Finally, we can calculate the mass lost:

Mass Lost = (22 × 5.8 × 3600 × 0.25) / (2.9 × 10^7)

Evaluating the expression, we find the mass lost by the cyclist.