Posted by Alyssa on Tuesday, April 12, 2011 at 10:20am.
How would you go about solving this? Im totally confused. Thanks!
Find the value of k such that the graph of f contains the given point. Write k as a simplified fraction if it is not a whole number.
f(x) = kx^3  3x^2 + kx + 3; (1, 8)

algebra  Henry, Wednesday, April 13, 2011 at 9:16pm
Y = K(1)^33(1)^2+K(1)+3 = 8,
K3K+3 = 8,
2K = 8,
K = 4.