How would you go about solving this? Im totally confused. Thanks!
Find the value of k such that the graph of f contains the given point. Write k as a simplified fraction if it is not a whole number.
f(x) = kx^3 - 3x^2 + kx + 3; (-1, 8)
algebra - Henry, Wednesday, April 13, 2011 at 9:16pm
Y = K(-1)^3-3(-1)^2+K(-1)+3 = 8,
-K-3-K+3 = 8,
-2K = 8,
K = -4.