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December 17, 2014

December 17, 2014

Posted by **Alyssa** on Tuesday, April 12, 2011 at 10:20am.

Find the value of k such that the graph of f contains the given point. Write k as a simplified fraction if it is not a whole number.

f(x) = kx^3 - 3x^2 + kx + 3; (-1, 8)

- algebra -
**Henry**, Wednesday, April 13, 2011 at 9:16pmY = K(-1)^3-3(-1)^2+K(-1)+3 = 8,

-K-3-K+3 = 8,

-2K = 8,

K = -4.

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