write the balanced molecular equation, the complete ionic equation and the net ionic equation.

copper(2) sulfate and 10% sodium hydroxide

CuSO4(aq) + 2NaOH(aq) ==> Cu(OH)2(s) + Na2SO4(aq)

C6+2(aq) + 2OH^-(aq) ==> Cu(OH)2(s)
You can do the complete ionic equation from the two I've done.

Thanks you very much. (:

That C6+2 should be Cu^+2

To write the balanced molecular equation, complete ionic equation, and net ionic equation for the reaction between copper(2) sulfate (CuSO4) and 10% sodium hydroxide (NaOH), you need to follow a step-by-step process:

Step 1: Write the balanced molecular equation
The molecular equation represents the reaction as a whole, without indicating the dissociation of the ionic compounds.

CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4

In this equation, CuSO4 reacts with 2NaOH to form Cu(OH)2 and Na2SO4.

Step 2: Write the complete ionic equation
The complete ionic equation shows all the ions involved in the reaction by dissociating the reactants and products into their ionic components.

Cu2+ + SO4^2- + 2Na+ + 2OH- -> Cu(OH)2 (s) + 2Na+ + SO4^2-

Here, CuSO4 dissociates into Cu2+ and SO4^2- ions, while NaOH dissociates into Na+ and OH- ions.

Step 3: Write the net ionic equation
The net ionic equation focuses only on the ions that participate in the reaction and removes the spectator ions (ions that exist in the same form on both the reactant and product sides).

Cu2+ + 2OH- -> Cu(OH)2 (s)

In the net ionic equation, the Na+ and SO4^2- ions are spectator ions and are not shown.

To summarize:
Balanced Molecular Equation: CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4
Complete Ionic Equation: Cu2+ + SO4^2- + 2Na+ + 2OH- -> Cu(OH)2 (s) + 2Na+ + SO4^2-
Net Ionic Equation: Cu2+ + 2OH- -> Cu(OH)2 (s)