Posted by Thao on Tuesday, April 12, 2011 at 12:20am.
Note the correct spelling of celsius.
Heat gained by ice + heat gained by melted water + heat lost by original water = 0
[mass ice x heat fusion] + [mass melted ice x specific water x (Tfinal-Tinitial)] + [mass 250mL water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for mass ice (and melted ice). I think something like 200 g ice is necessary but that is an aproximation.
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