Osmolarity (Osm) is the molar concentration of the particles-molecules and/or ions-in a solution. In physiological solutions, 5 \% ({\rm m/v}) glucose ({\rm C}_{6}{\rm H}_{12}{\rm O}_{6}) and 0.9 \% ({\rm m/v}) {\rm NaCl}, the osmolarity must be the same as for the blood, which is 0.3 {\rm Osm}.

1.Calculate the osmolarity of glucose in the solution.
2.Calculate the osmolarity of {\rm NaCl} in the solution.

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To calculate the osmolarity of a solution, we need to consider the molar concentrations of all the solute particles in the solution. In this case, we have two solutes: glucose (C6H12O6) and NaCl.

1. To calculate the osmolarity of glucose in the solution:
First, we need to determine the molar concentration of glucose in the solution. We are given that the solution contains 5% (m/v) glucose. This means that 5g of glucose is present in 100mL of the solution.
To convert this mass concentration to molar concentration, we need to know the molar mass of glucose. The molar mass of glucose is 180.16 g/mol.

So, we can calculate the molar concentration of glucose as follows:
Molar concentration of glucose = (mass of glucose / molar mass of glucose) / volume of solution
Molar concentration of glucose = (5g / 180.16 g/mol) / 0.1 L

Calculating this, we get:
Molar concentration of glucose = 0.0277 mol/L

Since osmolarity is expressed in osmoles per liter (Osm/L), the osmolarity of glucose in the solution is also 0.0277 Osm.

2. To calculate the osmolarity of NaCl in the solution:
Similar to the previous calculation, we need to determine the molar concentration of NaCl in the solution. We are given that the solution contains 0.9% (m/v) NaCl. This means that 0.9g of NaCl is present in 100mL of the solution.
To convert this mass concentration to molar concentration, we need to know the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol.

So, we can calculate the molar concentration of NaCl as follows:
Molar concentration of NaCl = (mass of NaCl / molar mass of NaCl) / volume of solution
Molar concentration of NaCl = (0.9g / 58.44 g/mol) / 0.1 L

Calculating this, we get:
Molar concentration of NaCl = 0.1545 mol/L

Therefore, the osmolarity of NaCl in the solution is 0.1545 Osm.