1) When electrons are forced away from a/an ___ plate, work is done.
Is "positive" a possible answer?
2) Any pointed or angular surface of an object must have a/an ___ concentration of charge to establish equilibrium.
Any ideas?
1, Postive plate is correct. It takes work to move an electron from where it wants to go.
2. Poorly worded. If a conducting surface is at equal potential, the charge density at the point is higher due to the smaller surface area, which leads to a much higher Electric field at the point.
So I think maybe "higher" is what the author wanted, but it is higher charge density (due to smaller surface area). Maybe "concentration" is being used to indicate charge density.
1) When electrons are forced away from a negative plate, work is done.
To understand this, we need to recall the concept of electric potential difference between two points. Electric potential is the amount of work needed to move a unit positive charge from one point to another, while electric potential difference is the change in electric potential between two points.
In an electric circuit, when a battery is connected to two plates, one positive and one negative, the battery creates an electric potential difference between the plates. This means that the positive plate has a higher electric potential compared to the negative plate. This potential difference creates an electric field that forces electrons (which are negatively charged) to move away from the negative plate towards the positive plate. Since work is done to overcome the electric forces and move the electrons, we can say that electrons are forced away from the negative plate.
On the other hand, if we consider a positive plate, electrons move towards the positive plate rather than being forced away from it. Therefore, "positive" is not the correct answer.
2) Any pointed or angular surface of an object must have a higher concentration of charge to establish equilibrium.
To explain this, we need to consider the concept of charge distribution and how it affects the electric field around an object. When a charge is distributed on an object, it creates an electric field in its surroundings. The direction and strength of the electric field depend on the charge distribution.
For a pointed or angular surface, the curvature of the surface causes charge to accumulate more in certain regions compared to others. This non-uniform distribution of charge creates a non-uniform electric field around the object. The electric field tends to be stronger around regions of higher charge concentration and weaker around regions of lower charge concentration.
To establish equilibrium, where the electric forces balance each other out, the charge distribution on the object needs to adjust accordingly. In the case of a pointed or angular surface, the concentration of charge must be higher at the pointed or angular regions compared to the rest of the surface. This allows the electric field to be more uniform and balanced, resulting in equilibrium.
Hence, a pointed or angular surface must have a higher concentration of charge to establish equilibrium.