Posted by math student 7 on .
A gardener wants to fence the largest possible rectangular area using 200 yards of fencing. Find the best length and width of the garden.

Math 
math student 7,
please help me!

Math 
Ms. Sue,
The largest area is a square.
P = 4S
200/4 = S 
Math 
math student 7,
even if it said rectangular?
so its's 50 yd by 50 yd? 
Math 
math student 7,
I also need help on this question:
Sandra walked to the top of a hill at a speed of 2km/h, turned around and walked down the hill at a rate of 4km/h. The whole trip took 6 hoours. How many kilometers is it to the top of the hill?
I thought it might be 6km but my math teacher checked it and said it wasn't. 
Math 
math student 7,
hello?Ms. Sue????

Math 
Ms. Sue,
A square is a rectangle. Yes. The largest area would be a square measuring 50 yards on each side.
Her average speed is 3 km/hour.
(3 * 6)/2 = ? 
Math 
Bosnian,
W=Width
L=Length
P=Perimeter
A=Area
P=2(W+L)
200=2(W+L) Divide with 2
100=W+L
100L=W
W=100L
A=W*L=(100L)*L
A=100LL^2
dA/dL=1002L
Function has minimum or maximum when first derivate=0
1002L=0
100=2L Divide with 2
50=L
L=50 yd
If second derivate<0 then function has a maximum.
If second derivate>0 then function has a minimum.
Second derivate=2<0
function has a maximum for L=50 yd
W=100L
W=10050=50 yd
A(max)=50*50=2500 yd^2 
Math 
math student 7,
what do you do with (*)

Math 
Bosnian,
* is sign for multiply