Posted by Nicole on Monday, April 11, 2011 at 4:54pm.
Let's call CH3COOH HA and the acetate ion will be A-
millimoles HA = 500 mL x 0.30M = 150.
mmoles A- = 500 mL x 0.20M = 100
We will add 93mL x 1.00M = 93 mmoles NaOH.
............HA + OH- ==> A- + H2O
initial....150...0.......100......
add..............93................
change.....-93...-93.....+93...+93
equil.......57....0......193
pH = pKa + log(base)/(acid)
Plug and chug.
My quickie answer is 5.3 but you should confirm that and don't estimate as I've done.
Related Questions
Buffer Solution - You have 500.0 mL of a buffer solution containing 0.30 M ...
school - What is the pH of 0.1 M formic acid solution? Ka=1.7„e10-4? What ...
chemistry - If you add 5.0 mL of 0.50 M NaOH solution to 20.0 mL to Buffer C, ...
chem - make 300.0 mL of a pH 5.30 buffer from 0.500 M acetic acid and 0.500 M ...
chem - make 300.0 mL of a pH 5.30 buffer from 0.500 M acetic acid and 0.500 M ...
chemistry - If you add 5.0 mL of 0.50 M HCl solution to 20.0 mL to Buffer C, ...
chemistry-science - A 500 ml buffer solution contains .2M Acetic acid and .3M ...
Buffer Solutions - A buffered solution is made by adding 75.0g sodium acetate to...
chemistry - a buffer is made by mixing 0.1 moles of acetic acd a sodium acetate ...
Chemistry - I did an experiment on Buffers: In a polystyrene beaker, mix 20 ml ...
For Further Reading
