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Posted by on Monday, April 11, 2011 at 8:00am.

A steel rod of length 1.0000 m and cross-sectional area 3.63·10-4m2 is placed snugly against two immobile end points. The rod is initially placed when the temperature is 0°C. Find the stress in the rod when the temperature rises to 38.9°C.

  • physic - , Monday, April 11, 2011 at 12:28pm

    Thermal expansion equals stress compression. Solve for the stress, sigma.

    L*(alpha)*(delta T) = (sigma/E)*L

    sigma = E*(alpha)*(deltaT)

    E is Young's modulus for steel
    delta T = 38.9 C

    alpha is the linear coefficient of thermal expansionm of styel
    L cancels out and is not needed.

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