2cos(theda)-"2=0

To solve the equation 2cos(theta) - 2 = 0, we can follow these steps:

Step 1: Add 2 to both sides of the equation:
2cos(theta) - 2 + 2 = 0 + 2
2cos(theta) = 2

Step 2: Divide both sides of the equation by 2:
(2cos(theta))/2 = 2/2
cos(theta) = 1

Step 3: Now, we need to find the values of theta for which cos(theta) is equal to 1. Remember that cos(theta) represents the cosine of an angle theta, which is the ratio of the adjacent side to the hypotenuse in a right-angled triangle.

The cosine function has a period of 2π, meaning that it repeats every 2π radians (or 360 degrees). At multiple points along the unit circle, the cosine value is equal to 1.

Therefore, the solutions for theta can be expressed as follows:
theta = 2nπ, where n is an integer.

In other words, any angle that is a multiple of 2π radians (or 360 degrees) will satisfy the equation.

For example, some possible values of theta that satisfy the equation are:
theta = 0 radians
theta = 2π radians
theta = 4π radians
theta = 6π radians
...

Please note that the solutions can also be written in degrees, where theta = 0 degrees, theta = 360 degrees, theta = 720 degrees, and so on.