Posted by **Hester** on Sunday, April 10, 2011 at 8:35pm.

A bridge is 40.0 m. A car weighs 1.5 x 10^4 N and it is parked with its center of gravity located 12.0 meters from the right pier. What upward support force must be provided by the left pier?

- Physics -
**bobpursley**, Sunday, April 10, 2011 at 8:39pm
draw the figure. Put the weight of the bridge in the center, and the car as determined.

Sum moments about the right pier.

clockwise positive.

LeftPierforceup*40-weightbridge*20-weightcar*12=0

so, if you know the weight of the bridge, you have it. Surely you don't want to ignore that, however, your teacher is your teacher.

## Answer This Question

## Related Questions

- Physics center of gravity - a uniform bridge span weighs 50000N and is 40m long...
- COLLEGE PHYSICS - a uniform bridge span weighs 50x10^3 and is 40m long. A car ...
- physics - A bridge of length 22 m and mass 1.5 × 105 kg is supported at each end...
- physics - A 75.0 kN truck is parked in the middle of a 20.0 m long bridge. How ...
- Physics - A hiker who weighs 834N, is strolling through the woods and crosses a ...
- physics - A hiker who weighs 889 N, is strolling through the woods and crosses a...
- PHYSICS - A hiker, who weighs 976 N, is strolling through the woods and crosses ...
- PHYSICS - A hiker, who weighs 977 N, is strolling through the woods and crosses ...
- physics - A hiker, who weighs 1120 N, is strolling through the woods and crosses...
- Physics - A hiker, who weighs 990 N, is strolling through the woods and crosses...

More Related Questions