Posted by Dan on Sunday, April 10, 2011 at 5:36pm.
An 9.00cmdiameter, 400 sphere is released from rest at the top of a 1.90mlong, 20.0 incline. It rolls, without slipping, to the bottom.
A) What is the sphere's angular velocity at the bottom of the incline?
B) WWhat fraction of its kinetic energy is rotational?

Physics  bobpursley, Sunday, April 10, 2011 at 5:53pm
mgh=rotational energy + translational energy
I assume the 20 is an angle
mg(1.90 sin20)=1/2 I w^2+1/2 mv^2
but v=wr so
= 1/2 I w^2+1/2 m w^2 r^2
so calculate w.
then you have the two terms, and the total energy, solve for the fraction.