Posted by **Dan** on Sunday, April 10, 2011 at 5:36pm.

An 9.00-cm-diameter, 400 sphere is released from rest at the top of a 1.90-m-long, 20.0 incline. It rolls, without slipping, to the bottom.

A) What is the sphere's angular velocity at the bottom of the incline?

B) WWhat fraction of its kinetic energy is rotational?

- Physics -
**bobpursley**, Sunday, April 10, 2011 at 5:53pm
mgh=rotational energy + translational energy

I assume the 20 is an angle

mg(1.90 sin20)=1/2 I w^2+1/2 mv^2

but v=wr so

= 1/2 I w^2+1/2 m w^2 r^2

so calculate w.

then you have the two terms, and the total energy, solve for the fraction.

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