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Posted by on Sunday, April 10, 2011 at 5:36pm.

An 9.00-cm-diameter, 400 sphere is released from rest at the top of a 1.90-m-long, 20.0 incline. It rolls, without slipping, to the bottom.
A) What is the sphere's angular velocity at the bottom of the incline?
B) WWhat fraction of its kinetic energy is rotational?

  • Physics - , Sunday, April 10, 2011 at 5:53pm

    mgh=rotational energy + translational energy
    I assume the 20 is an angle
    mg(1.90 sin20)=1/2 I w^2+1/2 mv^2
    but v=wr so

    = 1/2 I w^2+1/2 m w^2 r^2

    so calculate w.

    then you have the two terms, and the total energy, solve for the fraction.

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