Posted by John - PLEASE Help! on Sunday, April 10, 2011 at 4:46pm.
No more than 120/35 = 3.43 A could flow if the resistors were in series. Theretore I mus assume that they are in parallel and that 11-3.43 = 7.57 A flows through the unknown resistor. Use that fact and the 120 V applied voltage to get its resistance, R = V/I = 15.85 ohms
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