geometry
posted by Chanell on .
if x+y=11, y+z=14, and x+z=13, what is the value of x+y+z ?

Eq1: X + Y = 11.
Eq2: Y + Z = 14.
Y = 14  Z.
Eq3: X + Z = 13.
X = 13  Z.
In Eq1, substitute (13Z) for X, and
(14Z) for Y:
(13Z) + (14Z) = 11,
13  Z + 14  Z = 11,
2Z + 27 = 11,
2Z = 11  27 = 16,
Z = 8.
X + Y + Z,
Substitute 11 for y and 8 for Z:
(X+Y)+Z = 11 + 8 = 19. 
CORRECTION:
Substitute 11 for (x+y).