Homework Help: Chemistry

Posted by Nana on Sunday, April 10, 2011 at 2:45pm.

What is the pH of a solution that is 0.40 M in sulfurous acid (H2SO3) and )0.22 M in sodium sulfite (NaHSO3-)? Ka (H2SO3) = 1.3x10-2

Chemistry - DrBob222, Sunday, April 10, 2011 at 7:15pm
Use the Henderson-Hasselbalch equation.
pH = pKa + log (base)/(acid).
Chemistry - Nana, Sunday, April 10, 2011 at 9:08pm
Thanks :) I did that and got 1.63 as my pH, which is the correct answer.

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