calculus
posted by ben on .
Please help. I need ( with details) how to differentiate with the chain rule f(x)=(x^26x+23)^3/2. I need to

f = u^n where u=x^26x_23
note that du=2x6
so
f'= nu^(n1)* du
where n= 1.5
posted by ben on .
Please help. I need ( with details) how to differentiate with the chain rule f(x)=(x^26x+23)^3/2. I need to
f = u^n where u=x^26x_23
note that du=2x6
so
f'= nu^(n1)* du
where n= 1.5