Homework Help: Math HELP!!!

Posted by Kylie<3 on Sunday, April 10, 2011 at 1:34pm.

HELP!!!
I dont understand the question and need an asnwer fast!

Two different memberships are available at a discount department store. The Type A membership costs $200 and allows you to enter the store and take 75% off the marked price. The Type B membership costs $50 and allows you to enter the store and pay 62.5% of the marked price.

Type A membership: c = 0.25p + $200
Type B membership: c = 0.625p + $50

How many dollars worth of merchandise would a person have to buy for the cost of the Type A membership to equal the cost of the Type B membership?

Math HELP!!! - Kylie<3, Sunday, April 10, 2011 at 2:06pm
Really? anyone???
Math HELP!!! - Henry, Tuesday, April 12, 2011 at 11:06am
When A = B,
0.25p + 200 = 0.625p + 50,
0.25p - 0.625p = 50 - 200,
-0.375p = -150,
P = $400.
Math HELP!!! - Henry, Tuesday, April 12, 2011 at 11:13am
When A = B,
0.25p + 200 = 0.625p + 50,
0.25p - 0.625p = 50 - 200,
-0.375p = -150,
P = $400.
Math HELP!!! - JSHJHDH, Tuesday, April 2, 2013 at 6:25pm
The booster club sold tickets to a high school basketball game. They sold 700 student tickets and 500 general admission tickets, and raised a total of $5000. The combined cost of one student ticket and one general admission ticket was $8.

The equations and graph below can be used to determine how much each ticket type cost, where s represents the cost of one student ticket and g represents the cost of one general admission ticket.

Total ticket sales: 700s + 500g = $5000
Total cost for one student and one general admission ticket: s + g = 8

What was the price, in dollars, of a general admission ticket?

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