Posted by **Anonymous** on Sunday, April 10, 2011 at 12:44am.

A 828 mL sample of NO2 gas is at STP. If the volume changes to 598 mL and the temperature changes to 12ºC, what will be the new pressure in atmospheres?

new pressure=_____atm

- chemistry -
**Jai**, Sunday, April 10, 2011 at 12:55am
assuming the gas is ideal, we can use the formula,

P1*V1/T1 = P2*V2/T2

where

P1 = initial pressure

V1 = initial volume

T1 = initial temperature (in K)

P2 = final pressure

V2 = final volume

T2 = final temperature (in K)

we first convert the given temp to Kelvin units:

T2 = 12 + 273.15 = 285.15 K

*then note that at STP, temp is at 273.15 K and 1 atm. substituting,

P1*V1/T1 = P2*V2/T2

(1)(828) / 273.15 = (P2)(598) / 285.15

P2 = (828)(285.15) / (273.15)(598)

P2 = 1.45 atm

hope this helps~ :)

- chemistry -
**Anonymous**, Sunday, April 10, 2011 at 1:30am
thank you very much it does help a lot but when im doing this problems on my oown they dnt make any sense ..

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