A sample of a gas at 0.63 atm occupies a volume of 324 mL. If the temperature remains constant, what will be the new pressure if the volume increases to 124 mL?

new pressure=_____atm

umm i think in the problem, you mean "the volume DECREASES",,

assuming the gas ideal, we can use the formula
P1*V1 = P2*V2
where
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
*this equation is Boyle's Law
substituting,
0.63 * 324 = P2 * 124
P2 = 0.63 * 324 / 124
P2 = 1.65 atm

hope this helps~ :)

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Sra

To find the new pressure, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature remains constant. Boyle's Law can be written as:

P1 * V1 = P2 * V2

Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure (what we need to find)
V2 = final volume

Given:
P1 = 0.63 atm
V1 = 324 mL
V2 = 124 mL

We can plug in these values into Boyle's Law equation and solve for P2:

P1 * V1 = P2 * V2
0.63 atm * 324 mL = P2 * 124 mL

Solving for P2:

P2 = (0.63 atm * 324 mL) / 124 mL
P2 = 1.644

Therefore, the new pressure will be approximately 1.644 atm.