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January 30, 2015

January 30, 2015

Posted by **j** on Saturday, April 9, 2011 at 7:58pm.

- calculus -
**bobpursley**, Saturday, April 9, 2011 at 9:21pmVolume=a^2 h

cost= 4.25*a^2 + 2.5*(4 a*h)

dV/da=2ah+a^2 dh/da=0

but on the cost equation

take the derivative of Cost respect to a

0=8.5a+10h+ 10a*dh/da

but in the volume equation we can find

dh/da=-2ah/a^2=-2h/a

put that into the derivative of the cost

0=8.5a+10h+10 a(-2h/a)

0=8.5a-10h

h=.85a

now you can put that into the cost equation, with cost at 500, and solve for a, then h.

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